Question 1 · difficulty L2 · understanding
The hydrogen electrode is dipped in a solution of pH=3 at 25∘C. The potential of the electrode will be _________ ×10−2 V. (F2.303RT=0.059 V)
Question 2 · difficulty L2 · understanding
In a cell, the following reactions take place \begin{aligned}\matrix{ {F{e^{2 + }} \to F{e^{3 + }} + {e^ - }} & {E_{F{e^{3 + }}/F{e^{2 + }}}^o = 0.77\,V} \cr {2{I^ - } \to {I_2} + 2{e^ - }} & {E_{{I_2}/{I^ - }}^o = 0.54\,V} \cr } \end{aligned} The standard electrode potential for the spontaneous reaction in the cell is x × 10 −2 V 298 K. The value of x is ____________. (Nearest Integer)
Question 3 · difficulty L2 · understanding
Given at 298 K : EFe2+/Fe⊖=X Volt EFe3+/Fe⊖=Y Volt The EFe3+/Fe2+⊖ in Volt at 298 K is given by :
- A. 2X−3Y
- B. 3Y−2X
- C. 3Y+2X
- D. Y+X
Question 4 · difficulty L2 · understanding
Consider the following reduction processes : Al3++3e−⟶Al( s),E0=−1.66 VFe3++e−⟶Fe2+,E0=+0.77 VCo3++e−⟶Co2+,E0=+1.81 VCr3++3e−⟶Cr( s),E0=−0.74 V The tendency to act as reducing agent decreases in the order :
- A. Al>Fe2+>Cr>Co2+
- B. Al>Cr>Co2+>Fe2+
- C. Cr>Fe2+>Al>Co2+
- D. Al>Cr>Fe2+>Co2+
Question 5 · difficulty L2 · understanding
The standard reduction potential values of some of the p-block ions are given below. Predict the one with the strongest oxidising capacity.
- A. ESn4+/Sn2+o=+1.15 V
- B. EAl3+/Alo=−1.66 V
- C. EPb4+/Pb2+o=+1.67 V
- D. ETl3+/Tlo=+1.26 V
Question 6 · difficulty L2 · understanding
Based on the data given below : ECr2O72−/Cr3+∘=1.33 VEMnO4−/Mn2+0=1.51 VECl2/Cl(−)∘=1.36 VECr3+/Cr∘=−0.74 V the strongest reducing agent is :
- A. Cl−
- B. MnO4−
- C. Cr
- D. Mn2+
Question 7 · difficulty L2 · understanding
One of the commonly used electrode is calomel electrode. Under which of the following categories, calomel electrode comes?
- A. Metal ion - Metal electrodes
- B. Oxidation - Reduction electrodes
- C. Metal - Insoluble Salt - Anion electrodes
- D. Gas - Ion electrodes
Question 8 · difficulty L2 · understanding
Reduction potential of ions are given below: ClO4−E∘=1.19 VIO4−E∘=1.65 VBrO4−E∘=1.74 V The correct order of their oxidising power is :
- A. IO4−>BrO4−>ClO4−
- B. BrO4−>ClO4−>IO4−
- C. ClO4−>IO4−>BrO4−
- D. BrO4−>IO4−>ClO4−
Question 9 · difficulty L2 · understanding
In 3d series, the metal having the highest M 2+ /M standard electrode potential is :
Question 10 · difficulty L2 · understanding
The (∂T∂E)P of different types of half cells are as follows: A B C D 1×10−4 2×10−4 0.1×10−4 0.2×10−4 (Where E is the electromotive force) Which of the above half cells would be preferred to be used as reference electrode?