Question 1 · difficulty L2 · understanding
Complete the following reaction sequence and give the name of major product ’ P ’.
- A. 2-Chloropropanoic acid
- B. 3-Chloropropanoic acid
- C. 1-Chloropropane
- D. 2-Chloropropane
Question 2 · difficulty L2 · understanding
Which among the followng has highest boiling point?
- A. CH3CH2CH2CH2−OH
- B. CH3CH2CH2CH3
- C. CH3CH2CH2CHO
- D. H5C2−O−C2H5
Question 3 · difficulty L2 · understanding
The molecular formula of second homologue in the homologous series of mono carboxylic acids is
- A. C2H4O2
- B. C2H2O2
- C. CH2O
- D. C3H6O2
Question 4 · difficulty L2 · understanding
The two products formed in above reaction are -
- A. Butanal and acetaldehyde
- B. Butanoic acid and acetic acid
- C. Butanal and acetic acid
- D. Butanoic acid and acetaldehyde
Question 5 · difficulty L2 · understanding
Which one of the following compounds will liberate CO 2 , when treated with NaHCO 3 ?
- A. (CH3)3NH⊕ClΘ
- B. (CH3)4N⊕OΘH
- D. CH3NH2
Question 6 · difficulty L2 · understanding
The total number of 'Sigma' and 'Pi' bonds in 2-formylhex-4-enoic acid is _________.
Question 7 · difficulty L2 · understanding
Consider the above reaction where 6.1 g of Benzoic acid is used to get 7.8 g of m-bromo benzoic acid. The percentage yield of the product is __________ (Round off to the Nearest Integer). [Given : Atomic masses : C : 12.0 u, H : 1.0 u, O : 16.0 u, Br : 80.0 u]
Question 8 · difficulty L2 · understanding
The number of compound/s given below which contain/s -COOH group is __________. (Integer answer) (A) Sulphanilic acid (B) Picric acid (C) Aspirin (D) Ascorbic acid
Question 9 · difficulty L2 · understanding
The carboxyl functional group (−COOH) is present in
- A. picric acid
- B. barbituric acid
- C. ascorbic acid
- D. aspirin
Question 10 · difficulty L2 · understanding
The correct order of decreasing acidity of the following aliphatic acids is
- A. HCOOH>CH3COOH>(CH3)2CHCOOH>(CH3)3CCOOH
- B. HCOOH>(CH3)3CCOOH>(CH3)2CHCOOH>CH3COOH
- C. (CH3)3CCOOH>(CH3)2CHCOOH>CH3COOH>HCOOH
- D. CH3COOH>(CH3)2CHCOOH>(CH3)3CCOOH>HCOOH