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NEET-UG Biology

Arithmetic and geometric progressions — practice questions

112 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    Let A1, A2, A3,..,A39\mathrm{A}_1, \mathrm{~A}_2, \mathrm{~A}_3, \ldots \ldots . ., \mathrm{A}_{39} be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25, A28, A31\mathrm{A}_{25}, \mathrm{~A}_{28}, \mathrm{~A}_{31} and A36\mathrm{A}_{36} is equal to :

    • A. 129
    • B. 136
    • C. 131.50
    • D. 134
  2. Question 2 · difficulty L2 · understanding

    In an arithmetic progression, if S40=1030\mathrm{S}_{40}=1030 and S12=57\mathrm{S}_{12}=57, then S30S10\mathrm{S}_{30}-\mathrm{S}_{10} is equal to :

    • A. 525
    • B. 505
    • C. 510
    • D. 515
  3. Question 3 · difficulty L2 · understanding

    Let SnS_n denote the sum of first nn terms of an arithmetic progression. If S20=790S_{20}=790 and S10=145S_{10}=145, then S15S5\mathrm{S}_{15}-\mathrm{S}_5 is :

    • A. 405
    • B. 390
    • C. 410
    • D. 395
  4. Question 4 · difficulty L2 · understanding

     The 20th  term from the end of the progression 20,1914,1812,1734,,12914 is : \text { The } 20^{\text {th }} \text { term from the end of the progression } 20,19 \frac{1}{4}, 18 \frac{1}{2}, 17 \frac{3}{4}, \ldots,-129 \frac{1}{4} \text { is : }

    • A. 115-115
    • B. 100-100
    • C. 110-110
    • D. 118-118
  5. Question 5 · difficulty L2 · understanding

    Let S n denote the sum of first n-terms of an arithmetic progression. If S 10 = 530, S 5 = 140, then S 20 - S 6 is equal to:

    • A. 1862
    • B. 1842
    • C. 1852
    • D. 1872
  6. Question 6 · difficulty L2 · understanding

    Let a1,a2,,a2024a_1, a_2, \ldots, a_{2024} be an Arithmetic Progression such that a1+(a5+a10+a15++a2020)+a2024=2233a_1+\left(a_5+a_{10}+a_{15}+\ldots+a_{2020}\right)+a_{2024}=2233. Then a1+a2+a3++a2024a_1+a_2+a_3+\ldots+a_{2024} is equal to _________.

  7. Question 7 · difficulty L3 · understanding

    Let α=3+4+8+9+13+14+\alpha=3+4+8+9+13+14+\ldots upto 40 terms. If (tanβ)α1020(\tan \beta)^{\frac{\alpha}{1020}} is a root of the equation x2+x2=0,β(0,π2)x^2+x-2=0, \beta \in\left(0, \frac{\pi}{2}\right), then sin2β+3cos2β\sin ^2 \beta+3 \cos ^2 \beta is equal to :

    • A. 2{ }2
    • B. 74{\frac{7}{4}}
    • C. 52\frac{5}{2}
    • D. 32\frac{3}{2}
  8. Question 8 · difficulty L3 · understanding

    Consider the quadratic equation (n22n+2)x23x+(n22n+2)2=0,nR\left(n^2-2 n+2\right) x^2-3 x+\left(n^2-2 n+2\right)^2=0, n \in \mathbf{R}. Let α\alpha be the minimum value of the product of its roots and β\beta be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is α\alpha and the common ratio is αβ\frac{\alpha}{\beta}, is :

    • A. 6137\frac{61}{37}
    • B. 12181\frac{121}{81}
    • C. 364243\frac{364}{243}
    • D. 1093729\frac{1093}{729}
  9. Question 9 · difficulty L3 · understanding

    The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is:

    • A. 349\frac{34}{9}
    • B. 3413\frac{34}{13}
    • C. 329\frac{32}{9}
    • D. 3213\frac{32}{13}
  10. Question 10 · difficulty L3 · understanding

    Let α,β\alpha, \beta be the roots of the equation x2x+p=0x^2-x+\mathrm{p}=0 and γ,δ\gamma, \delta be the roots the equation x24x+q=0x^2-4 x+\mathrm{q}=0; p,qZp, q \in \mathbf{Z}. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in G.P., then p+q|p+q| equals :

    • A. 16
    • B. 32
    • C. 34
    • D. 38

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