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NEET-UG Biology

Integration by substitution, by parts and by partial fractions — practice questions

41 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    The integral (2x1)cos(2x1)2+54x24x+6dx\int {{{(2x - 1)\cos \sqrt {{{(2x - 1)}^2} + 5} } \over {\sqrt {4{x^2} - 4x + 6} }}} dx is equal to (where c is a constant of integration)

    • A. 12sin(2x1)2+5+c{1 \over 2}\sin \sqrt {{{(2x - 1)}^2} + 5} + c
    • B. 12cos(2x+1)2+5+c{1 \over 2}\cos \sqrt {{{(2x + 1)}^2} + 5} + c
    • C. 12cos(2x1)2+5+c{1 \over 2}\cos \sqrt {{{(2x - 1)}^2} + 5} + c
    • D. 12sin(2x+1)2+5+c{1 \over 2}\sin \sqrt {{{(2x + 1)}^2} + 5} + c
  2. Question 2 · difficulty L3 · understanding

    If (sinx)112(cosx)52dx=p1q1(cotx)92p2q2(cotx)52p3q3(cotx)12+p4q4(cotx)32+C\int(\sin x)^{\frac{-11}{2}}(\cos x)^{\frac{-5}{2}} d x= -\frac{p_1}{q_1}(\cot x)^{\frac{9}{2}}-\frac{p_2}{q_2}(\cot x)^{\frac{5}{2}}-\frac{p_3}{q_3}(\cot x)^{\frac{1}{2}}+\frac{p_4}{q_4}(\cot x)^{\frac{-3}{2}}+\mathrm{C}, where pip_i and qiq_i are positive integers with gcd(pi,qi)=1\operatorname{gcd}\left(p_i, q_i\right)=1 for i=1,2,3,4i=1,2,3,4 and C is the constant of integration, then 15p1p2p3p4q1q2q3q4\frac{15 p_1 p_2 p_3 p_4}{q_1 q_2 q_3 q_4} is equal to ____\_\_\_\_

  3. Question 3 · difficulty L3 · understanding

    If (1x+1x3)(3x24+x2623)dx=α3(α+1)(3xβ+xγ)α+1α+C,x>0,(α,β,γZ)\int\left(\frac{1}{x}+\frac{1}{x^3}\right)\left(\sqrt[23]{3 x^{-24}+x^{-26}}\right) \mathrm{d} x=-\frac{\alpha}{3(\alpha+1)}\left(3 x^\beta+x^\gamma\right)^{\frac{\alpha+1}{\alpha}}+C, x>0,(\alpha, \beta, \gamma \in \mathbf{Z}), where C is the constant of integration, then α+β+γ\alpha+\beta+\gamma is equal to ___________.

  4. Question 4 · difficulty L3 · understanding

    If 1(x1)4(x+3)65 dx=A(αx1βx+3)B+C\int \frac{1}{\sqrt[5]{(x-1)^4(x+3)^6}} \mathrm{~d} x=\mathrm{A}\left(\frac{\alpha x-1}{\beta x+3}\right)^B+\mathrm{C}, where C\mathrm{C} is the constant of integration, then the value of α+β+20AB\alpha+\beta+20 \mathrm{AB} is _________.

  5. Question 5 · difficulty L3 · understanding

    If cosec5xdx=αcotxcosecx(cosec2x+32)+βlogxtanx2+C\int \operatorname{cosec}^5 x d x=\alpha \cot x \operatorname{cosec} x\left(\operatorname{cosec}^2 x+\frac{3}{2}\right)+\beta \log _x\left|\tan \frac{x}{2}\right|+\mathrm{C} where α,βR\alpha, \beta \in \mathbb{R} and C\mathrm{C} is the constant of integration, then the value of 8(α+β)8(\alpha+\beta) equals _________.

  6. Question 6 · difficulty L3 · understanding

    Let I(x)=x+7x dxI(x)=\int \sqrt{\frac{x+7}{x}} \mathrm{~d} x and I(9)=12+7loge7I(9)=12+7 \log _{e} 7. If I(1)=α+7loge(1+22)I(1)=\alpha+7 \log _{e}(1+2 \sqrt{2}), then α4\alpha^{4} is equal to _________.

  7. Question 7 · difficulty L3 · understanding

    If sinxsin3x+cos3xdx=\int {{{\sin x} \over {{{\sin }^3}x + {{\cos }^3}x}}dx = } αloge1+tanx+βloge1tanx+tan2x+γtan1(2tanx13)+C\alpha {\log _e}|1 + \tan x| + \beta {\log _e}|1 - \tan x + {\tan ^2}x| + \gamma {\tan ^{ - 1}}\left( {{{2\tan x - 1} \over {\sqrt 3 }}} \right) + C, when C is constant of integration, then the value of 18(α+β+γ2)18(\alpha + \beta + {\gamma ^2}) is ______________.

  8. Question 8 · difficulty L3 · understanding

    If 2ex+3ex4ex+7exdx=114(ux+vloge(4ex+7ex))+C\int {{{2{e^x} + 3{e^{ - x}}} \over {4{e^x} + 7{e^{ - x}}}}dx = {1 \over {14}}(ux + v{{\log }_e}(4{e^x} + 7{e^{ - x}})) + C} , where C is a constant of integration, then u + v is equal to _____________.

  9. Question 9 · difficulty L3 · understanding

    If dx(x2+x+1)2=atan1(2x+13)+b(2x+1x2+x+1)+C\int {{{dx} \over {{{({x^2} + x + 1)}^2}}} = a{{\tan }^{ - 1}}\left( {{{2x + 1} \over {\sqrt 3 }}} \right) + b\left( {{{2x + 1} \over {{x^2} + x + 1}}} \right) + C} , x > 0 where C is the constant of integration, then the value of 9(3a+b)9\left( {\sqrt 3 a + b} \right) is equal to _____________.

  10. Question 10 · difficulty L3 · understanding

    If f(x)=5x8+7x6(x2+1+2x7)2dx,(x0),f(0)=0f(x) = \int {{{5{x^8} + 7{x^6}} \over {{{({x^2} + 1 + 2{x^7})}^2}}}dx,(x \ge 0),f(0) = 0} and f(1)=1Kf(1) = {1 \over K}, then the value of K is

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