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NEET-UG Biology

Formation of differential equations — practice questions

15 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L3 · understanding

    If y1/4+y1/4=2x{y^{1/4}} + {y^{ - 1/4}} = 2x, and (x21)d2ydx2+αxdydx+βy=0({x^2} - 1){{{d^2}y} \over {d{x^2}}} + \alpha x{{dy} \over {dx}} + \beta y = 0, then | α\alpha - β\beta | is equal to __________.

  2. Question 2 · difficulty L3 · understanding

    Let a curve y = f(x) pass through the point (2, (log e 2) 2 ) and have slope 2yxlogex{{2y} \over {x{{\log }_e}x}} for all positive real value of x. Then the value of f(e) is equal to ______________.

  3. Question 3 · difficulty L3 · understanding

    Let f(x)f(x) be a positive function such that the area bounded by y=f(x),y=0y=f(x), y=0 from x=0x=0 to x=a>0x=a>0 is ea+4a2+a1e^{-a}+4 a^2+a-1. Then the differential equation, whose general solution is y=c1f(x)+c2y=c_1 f(x)+c_2, where c1c_1 and c2c_2 are arbitrary constants, is

    • A. (8ex+1)d2ydx2dydx=0\left(8 e^x+1\right) \frac{d^2 y}{d x^2}-\frac{d y}{d x}=0
    • B. (8ex+1)d2ydx2+dydx=0\left(8 e^x+1\right) \frac{d^2 y}{d x^2}+\frac{d y}{d x}=0
    • C. (8ex1)d2ydx2dydx=0\left(8 e^x-1\right) \frac{d^2 y}{d x^2}-\frac{d y}{d x}=0
    • D. (8ex1)d2ydx2+dydx=0\left(8 e^x-1\right) \frac{d^2 y}{d x^2}+\frac{d y}{d x}=0
  4. Question 4 · difficulty L3 · understanding

    The differential equation of the family of circles passing through the origin and having centre at the line y=xy=x is :

    • A. (x2y2+2xy)dx=(x2y2+2xy)dy\left(x^2-y^2+2 x y\right) \mathrm{d} x=\left(x^2-y^2+2 x y\right) \mathrm{d} y
    • B. (x2+y22xy)dx=(x2+y2+2xy)dy\left(x^2+y^2-2 x y\right) \mathrm{d} x=\left(x^2+y^2+2 x y\right) \mathrm{d} y
    • C. (x2+y2+2xy)dx=(x2+y22xy)dy\left(x^2+y^2+2 x y\right) \mathrm{d} x=\left(x^2+y^2-2 x y\right) \mathrm{d} y
    • D. (x2y2+2xy)dx=(x2y22xy)dy\left(x^2-y^2+2 x y\right) \mathrm{d} x=\left(x^2-y^2-2 x y\right) \mathrm{d} y
  5. Question 5 · difficulty L3 · understanding

    Let a differentiable function ff satisfy f(x)+\int_\limits{3}^{x} \frac{f(t)}{t} d t=\sqrt{x+1}, x \geq 3. Then 12f(8)12 f(8) is equal to :

    • A. 19
    • B. 34
    • C. 17
    • D. 1
  6. Question 6 · difficulty L3 · understanding

    The differential equation of the family of circles passing through the points (0,2)(0,2) and (0,2)(0,-2) is :

    • A. 2xydydx+(x2y2+4)=02 x y \frac{d y}{d x}+\left(x^{2}-y^{2}+4\right)=0
    • B. 2xydydx+(x2+y24)=02 x y \frac{d y}{d x}+\left(x^{2}+y^{2}-4\right)=0
    • C. 2xydydx+(y2x2+4)=02 x y \frac{d y}{d x}+\left(y^{2}-x^{2}+4\right)=0
    • D. 2xydydx(x2y2+4)=02 x y \frac{d y}{d x}-\left(x^{2}-y^{2}+4\right)=0
  7. Question 7 · difficulty L3 · understanding

    Let a smooth curve y=f(x)y=f(x) be such that the slope of the tangent at any point (x,y)(x, y) on it is directly proportional to (yx)\left(\frac{-y}{x}\right). If the curve passes through the points (1,2)(1,2) and (8,1)(8,1), then y(18)\left|y\left(\frac{1}{8}\right)\right| is equal to

    • A. 2loge22 \log _{e} 2
    • B. 4
    • C. 1
    • D. 4loge24 \log _{e} 2
  8. Question 8 · difficulty L3 · understanding

    Let dydx=axby+abx+cy+a,a,b,cR{{dy} \over {dx}} = {{ax - by + a} \over {bx + cy + a}},\,a,b,c \in R, represents a circle with center (α\alpha, β\beta). Then, α\alpha + 2β\beta is equal to :

    • A. -1
    • B. 0
    • C. 1
    • D. 2
  9. Question 9 · difficulty L3 · understanding

    Let dydx=axby+abx+cy+a{{dy} \over {dx}} = {{ax - by + a} \over {bx + cy + a}}, where a, b, c are constants, represent a circle passing through the point (2, 5). Then the shortest distance of the point (11, 6) from this circle is :

    • A. 10
    • B. 8
    • C. 7
    • D. 5
  10. Question 10 · difficulty L3 · understanding

    A differential equation representing the family of parabolas with axis parallel to y-axis and whose length of latus rectum is the distance of the point (2, -3) from the line 3x + 4y = 5, is given by :

    • A. 10d2ydx2=1110{{{d^2}y} \over {d{x^2}}} = 11
    • B. 11d2xdy2=1011{{{d^2}x} \over {d{y^2}}} = 10
    • C. 10d2xdy2=1110{{{d^2}x} \over {d{y^2}}} = 11
    • D. 11d2ydx2=1011{{{d^2}y} \over {d{x^2}}} = 10

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