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NEET-UG Biology

Scalar and vector products — practice questions

195 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    Let a=2i^+3j^+3k^\overrightarrow{\mathrm{a}}=2 \hat{i}+3 \hat{j}+3 \hat{k} and b=6i^+3j^+3k^\overrightarrow{\mathrm{b}}=6 \hat{i}+3 \hat{j}+3 \hat{k}. Then the square of the area of the triangle with adjacent sides determined by the vectors (2a+3b)(2 \vec{a}+3 \vec{b}) and (ab)(\vec{a}-\vec{b}) is :

    • A. 450
    • B. 900
    • C. 1800
    • D. 2400
  2. Question 2 · difficulty L2 · understanding

    Let a=2,b=3|\vec{a}|=2,|\vec{b}|=3 and the angle between the vectors a\vec{a} and b\vec{b} be π4\frac{\pi}{4}. Then (a+2b)×(2a3b)2|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^{2} is equal to :

    • A. 441
    • B. 482
    • C. 841
    • D. 882
  3. Question 3 · difficulty L2 · understanding

    Let a=5i^j^3k^\vec{a}=5 \hat{i}-\hat{j}-3 \hat{k} and b=i^+3j^+5k^\vec{b}=\hat{i}+3 \hat{j}+5 \hat{k} be two vectors. Then which one of the following statements is TRUE ?

    • A. Projection of a\vec{a} on b\vec{b} is 1335\frac{-13}{\sqrt{35}} and the direction of the projection vector is opposite to the direction of b\vec{b}.
    • B. Projection of a\vec{a} on b\vec{b} is 1335\frac{13}{\sqrt{35}} and the direction of the projection vector is opposite to the direction of b\vec{b}.
    • C. Projection of a\vec{a} on b\vec{b} is 1335\frac{13}{\sqrt{35}} and the direction of the projection vector is same as of b\vec{b}.
    • D. Projection of a\vec{a} on b\vec{b} is 1335\frac{-13}{\sqrt{35}} and the direction of the projection vector is same as of b\vec{b}.
  4. Question 4 · difficulty L2 · understanding

    Let a\vec{a} and b\vec{b} be two vectors, Let a=1,b=4|\vec{a}|=1,|\vec{b}|=4 and ab=2\vec{a} \cdot \vec{b}=2. If c=(2a×b)3b\vec{c}=(2 \vec{a} \times \vec{b})-3 \vec{b}, then the value of bc\vec{b} \cdot \vec{c} is :

    • A. 48-48
    • B. 60-60
    • C. 84-84
    • D. 24-24
  5. Question 5 · difficulty L2 · understanding

    Let a=i^+j^k^\overrightarrow a = \widehat i + \widehat j - \widehat k and c=2i^3j^+2k^\overrightarrow c = 2\widehat i - 3\widehat j + 2\widehat k. Then the number of vectors b\overrightarrow b such that b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a and b|\overrightarrow b | \in {1, 2, ........, 10} is :

    • A. 0
    • B. 1
    • C. 2
    • D. 3
  6. Question 6 · difficulty L2 · understanding

    Let a\vec{a} and b\vec{b} be two vectors such that a=14,b=6|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6} and a×b=48|\vec{a} \times \vec{b}|=\sqrt{48}. Then (ab)2(\vec{a} \cdot \vec{b})^{2} is equal to ___________.

  7. Question 7 · difficulty L3 · understanding

    Let a=4i^j^+3k^, b=10i^+2j^k^\overrightarrow{\mathrm{a}}=4 \hat{i}-\hat{j}+3 \hat{k}, \overrightarrow{\mathrm{~b}}=10 \hat{i}+2 \hat{j}-\hat{k} and a vector c\overrightarrow{\mathrm{c}} be such that 2(a×b)+3( b×c)=02(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}})+3(\overrightarrow{\mathrm{~b}} \times \overrightarrow{\mathrm{c}})=\overrightarrow{0}. If ac=15\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{c}}=15, then c(i^+j^3k^)\overrightarrow{\mathrm{c}} \cdot(\hat{i}+\hat{j}-3 \hat{k}) is equal to :

    • A. -6
    • B. -5
    • C. -4
    • D. -3
  8. Question 8 · difficulty L3 · understanding

    Let a=7i^+j^k^\vec{a}=\sqrt{7} \hat{i}+\hat{j}-\hat{k} and b=j^+2k^\vec{b}=\hat{j}+2 \hat{k}. If r\vec{r} is a vector such that r×a+a×b=0\vec{r} \times \vec{a}+\vec{a} \times \vec{b}=\overrightarrow{0} and ra=0\vec{r} \cdot \vec{a}=0, then 3r2|3 \vec{r}|^2 is equal to:

    • A. 44
    • B. 54
    • C. 86
    • D. 132
  9. Question 9 · difficulty L3 · understanding

    Let u^\hat{u} and v^\hat{v} be unit vectors inclined at an acute angle such that u^×v^=32|\hat{u} \times \hat{v}|=\frac{\sqrt{3}}{2}. If A=λu^+v^+(u^×v^)\overrightarrow{\mathrm{A}}=\lambda \hat{u}+\hat{v}+(\hat{u} \times \hat{v}), then λ\lambda is equal to:

    • A. 43( Au^)23( Av^) \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • B. 23( Au^)13( Av^) \frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{1}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • C. 43( Au^)+23( Av^) \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})+\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • D. (Au^)12( Av^) (\overrightarrow{\mathrm{A}} \cdot \hat{u})-\frac{1}{2}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
  10. Question 10 · difficulty L3 · understanding

    Let the vectors a=i^+j^+3k^\vec{a} = -\hat{i} + \hat{j} + 3\hat{k} and b=i^+3j^+k^\vec{b} = \hat{i} + 3\hat{j} + \hat{k}. For some λ,μR\lambda, \mu \in \mathbb{R}, let c=λa+μb\vec{c} = \lambda \vec{a} + \mu \vec{b}. If c(3i^6j^+2k^)=10\vec{c} \cdot (3\hat{i} - 6\hat{j} + 2\hat{k}) = 10 and c(i^+j^+k^)=2\vec{c} \cdot (\hat{i} + \hat{j} + \hat{k}) = -2, then c2|\vec{c}|^2 is equal to :

    • A. 8
    • B. 12
    • C. 14
    • D. 15

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