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NEET-UG Biology

Speed, velocity, uniform and non-uniform motion — practice questions

19 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    The position of a particle related to time is given by x=(5t24t+5)mx=\left(5 t^{2}-4 t+5\right) \mathrm{m}. The magnitude of velocity of the particle at t=2st=2 s will be :

    • A. 14 ms114 \mathrm{~ms}^{-1}
    • B. 16 ms116 \mathrm{~ms}^{-1}
    • C. 10 ms110 \mathrm{~ms}^{-1}
    • D. 06 ms106 \mathrm{~ms}^{-1}
  2. Question 2 · difficulty L2 · understanding

    The distance travelled by an object in time tt is given by s=(2.5)t2s=(2.5) t^{2}. The instantaneous speed of the object at t=5 s\mathrm{t}=5 \mathrm{~s} will be:

    • A. 5 ms15 \mathrm{~ms}^{-1}
    • B. 12.5 ms112.5 \mathrm{~ms}^{-1}
    • C. 62.5 ms162.5 \mathrm{~ms}^{-1}
    • D. 25 ms125 \mathrm{~ms}^{-1}
  3. Question 3 · difficulty L2 · understanding

    A person travels xx distance with velocity v1v_{1} and then xx distance with velocity v2v_{2} in the same direction. The average velocity of the person is v\mathrm{v}, then the relation between v,v1v, v_{1} and v2v_{2} will be.

    • A. V=V1+V2\mathbf{V}=\mathbf{V}_{1}+\mathbf{V}_{2}
    • B. V=v1+V22V=\frac{v_{1}+V_{2}}{2}
    • C. 1v=1v1+1v2\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}
    • D. 2 V=1v1+1v2\frac{2}{\mathrm{~V}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}
  4. Question 4 · difficulty L2 · understanding

    An object moves with speed v1,v2v_1,v_2 and v3v_3 along a line segment AB, BC and CD respectively as shown in figure. Where AB = BC and AD = 3AB, then average speed of the object will be:

    • A. v1v2v33(v1v2+v2v3+v3v1){{{v_1}{v_2}{v_3}} \over {3({v_1}{v_2} + {v_2}{v_3} + {v_3}{v_1})}}
    • B. (v1+v2+v3)3{{({v_1} + {v_2} + {v_3})} \over 3}
    • C. (v1+v2+v3)3v1v2v3{{({v_1} + {v_2} + {v_3})} \over {3{v_1}{v_2}{v_3}}}
    • D. 3v1v2v3(v1v2+v2v3+v3v1){{3{v_1}{v_2}{v_3}} \over {({v_1}{v_2} + {v_2}{v_3} + {v_3}{v_1})}}
  5. Question 5 · difficulty L2 · understanding

    A vehicle travels 4 km4 \mathrm{~km} with speed of 3 km/h3 \mathrm{~km} / \mathrm{h} and another 4 km4 \mathrm{~km} with speed of 5 km/h5 \mathrm{~km} / \mathrm{h}, then its average speed is

    • A. 3.75 km/h3.75 \mathrm{~km} / \mathrm{h}
    • B. 4.25 km/h4.25 \mathrm{~km} / \mathrm{h}
    • C. 3.50 km/h3.50 \mathrm{~km} / \mathrm{h}
    • D. 4.00 km/h4.00 \mathrm{~km} / \mathrm{h}
  6. Question 6 · difficulty L2 · understanding

    The distance travelled by a particle is related to time t as x=4t2x=4\mathrm{t}^2. The velocity of the particle at t=5s is :-

    • A. 25 ms1\mathrm{25~ms^{-1}}
    • B. 20 ms1\mathrm{20~ms^{-1}}
    • C. 8 ms1\mathrm{8~ms^{-1}}
    • D. 40 ms1\mathrm{40~ms^{-1}}
  7. Question 7 · difficulty L2 · understanding

    A car travels a distance of 'xx' with speed v1v_1 and then same distance 'xx' with speed v2v_2 in the same direction. The average speed of the car is :

    • A. v1v22(v1+v2){{{v_1}{v_2}} \over {2({v_1} + {v_2})}}
    • B. 2v1v2v1+v2{{2{v_1}{v_2}} \over {{v_1} + {v_2}}}
    • C. 2xv1+v2{{2x} \over {{v_1} + {v_2}}}
    • D. v1+v22{{{v_1} + {v_2}} \over 2}
  8. Question 8 · difficulty L2 · understanding

    If t=x+4\mathrm{t}=\sqrt{x}+4, then (dx dt)t=4\left(\frac{\mathrm{d} x}{\mathrm{~d} t}\right)_{\mathrm{t}=4} is :

    • A. 4
    • B. zero
    • C. 8
    • D. 16
  9. Question 9 · difficulty L2 · understanding

    The instantaneous velocity of a particle moving in a straight line is given as V=αt+βt2V = \alpha t + \beta {t^2}, where α\alpha and β\beta are constants. The distance travelled by the particle between 1s and 2s is :

    • A. 3α\alpha + 7β\beta
    • B. 32α+73β{3 \over 2}\alpha + {7 \over 3}\beta
    • C. α2+β3{\alpha \over 2} + {\beta \over 3}
    • D. 32α+72β{3 \over 2}\alpha + {7 \over 2}\beta
  10. Question 10 · difficulty L2 · understanding

    A person travelling on a straight line moves with a uniform velocity v1v_1 for a distance xx and with a uniform velocity v2v_2 for the next 32x\frac{3}{2} x distance. The average velocity in this motion is 507 m/s\frac{50}{7} \mathrm{~m} / \mathrm{s}. If v1v_1 is 5 m/s5 \mathrm{~m} / \mathrm{s} then v2=v_2= __________ m/s\mathrm{m} / \mathrm{s}.

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