Electric flux and Gauss's law with its applications — practice questions
56 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.
The electric field in a region is given by . The flux of the field through a rectangular surface parallel to plane is . The area of the surface is _____________ .
An electric field exists in space. A cube of side is placed in the space as per figure given below. The electric flux through the cube is ______ .
An electric field, passes through the surface of area having unit vector . The electric flux for that surface is _________ .
The electric field in a region is given by with . The flux of this field through a rectangular surface area 0.4 m 2 parallel to the Y-Z plane is __________ Nm 2 C 1 .
The electric field in a region is given by . The ratio of flux of reported field through the rectangular surface of area 0.2 m 2 (parallel to y z plane) to that of the surface of area 0.3 m 2 (parallel to x z plane) is a : b, where a = __________ [Here , and are unit vectors along x, y and z-axes respectively.]
Two point charges and are located at cm and cm, respectively on the -axis. The ratio of electric flux due to these charges through two spheres of radii 3 cm and 5 cm with their centers at the origin is ________.
- A. 4 : 1
- B. 3 : 4
- C. 4 : 3
- D. 4 : 5
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The outer body of an aircraft is made of metal which protects persons sitting inside from lightning strikes. Reason (R) : The electric field inside the cavity enclosed by a conductor is zero. In the light of the above statements, choose the most appropriate answer from the options given below :
- A. Both (A) and (R) are correct but (R) is not the correct explanation of (A)
- B. (A) is correct but (R) is not correct
- C. Both (A) and (R) are correct and (R) is the correct explanation of (A)
- D. (A) is not correct but (R) is correct
A point charge causes an electric flux of to pass through a spherical Gaussian surface of 8.0 cm radius, centred on the charge. The value of the point charge is : (Given )
- A.
- B.
- C.
- D.
Match List - I with List - II. List - I List - II (A) Electric field inside (distance r > 0 from center) of a uniformly charged spherical shell with surface charge density Ï, and radius R. (I) Ï/ε 0 (B) Electric field at distance r>0 from a uniformly charged infinite plane sheet with surface charge density Ï. (II) Ï/2ε 0 (C) Electric field outside (distance r>0 from center) of a uniformly charged spherical shell with surface charge density Ï, and radius R. (III) 0 (D) Electric field between 2 oppositely charged infinite plane parallel sheets with uniform surface charge density Ï. (IV) Choose the correct answer from the options given below :
- A. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- B. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- C. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
- D. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
Five charges and are situated as shown in the figure. The electric flux due to this configuration through the surface is :
- A.
- B.
- C.
- D.
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