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NEET-UG Biology

Resistivity, conductivity and temperature dependence — practice questions

30 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    At room temperature (27C)(27^{\circ} \mathrm{C}), the resistance of a heating element is 50Ω50 \Omega. The temperature coefficient of the material is 2.4×104C12.4 \times 10^{-4}{ }^{\circ} \mathrm{C}^{-1}. The temperature of the element, when its resistance is 62Ω62 \Omega, is __________C{ }^{\circ} \mathrm{C}.

  2. Question 2 · difficulty L2 · understanding

    A rectangular parallelopiped is measured as 1 cm×1 cm×100 cm1 \mathrm{~cm} \times 1 \mathrm{~cm} \times 100 \mathrm{~cm}. If its specific resistance is 3×107 Ωm3 \times 10^{-7} ~\Omega \mathrm{m}, then the resistance between its two opposite rectangular faces will be ___________ ×107 Ω\times 10^{-7} ~\Omega.

  3. Question 3 · difficulty L2 · understanding

    The length of a metallic wire is increased by 20%20 \% and its area of cross section is reduced by 4%4 \%. The percentage change in resistance of the metallic wire is __________.

  4. Question 4 · difficulty L2 · understanding

    A hollow cylindrical conductor has length of 3.14 m, while its inner and outer diameters are 4 mm and 8 mm respectively. The resistance of the conductor is n×103Ωn\times10^{-3}\Omega. If the resistivity of the material is 2.4×108Ωm\mathrm{2.4\times10^{-8}\Omega m}. The value of nn is ___________.

  5. Question 5 · difficulty L2 · understanding

    The length of a given cylindrical wire is increased to double of its original length. The percentage increase in the resistance of the wire will be ____________ %.

  6. Question 6 · difficulty L2 · understanding

    A wire of length 25 m and cross-sectional area 5 mm25 \mathrm{~mm}^2 having resistivity of 2×106Ω m2 \times 10^{-6} \Omega \mathrm{~m} is bent into a complete circle. The resistance between diametrically opposite points will be

    • A. 100Ω100 \Omega
    • B. 2.5Ω2.5 \Omega
    • C. 12.5Ω12.5 \Omega
    • D. 50Ω50 \Omega
  7. Question 7 · difficulty L2 · understanding

    Wheatstone bridge principle is used to measure the specific resistance (S1)\left(S_1\right) of given wire, having length LL, radius rr. If XX is the resistance of wire, then specific resistance is ; S1=X(πr2L)S_1=X\left(\frac{\pi r^2}{L}\right). If the length of the wire gets doubled then the value of specific resistance will be :

    • A. S14\frac{S_1}{4}
    • B. 2 S12 \mathrm{~S}_1
    • C. S12\frac{\mathrm{S}_1}{2}
    • D. S1S_1
  8. Question 8 · difficulty L2 · understanding

    A wire of resistance 160 Ω160 ~\Omega is melted and drawn in a wire of one-fourth of its length. The new resistance of the wire will be

    • A. 640 Ω640 ~\Omega
    • B. 40 Ω40 ~\Omega
    • C. 16 Ω16 ~\Omega
    • D. 10 Ω10 ~\Omega
  9. Question 9 · difficulty L2 · understanding

    The resistance of a wire is 5 Ω\Omega. It's new resistance in ohm if stretched to 5 times of it's original length will be :

    • A. 25
    • B. 625
    • C. 5
    • D. 125
  10. Question 10 · difficulty L2 · understanding

    Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Alloys such as constantan and manganin are used in making standard resistance coils. Reason R: Constantan and manganin have very small value of temperature coefficient of resistance. In the light of the above statements, choose the correct answer from the options given below.

    • A. Both A and R are true and R is the correct explanation of A.
    • B. Both A and R are true but R is NOT the correct explanation of A.
    • C. A is true but R is false.
    • D. A is false but R is true.

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