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NEET-UG Biology

Potentiometer - comparing emf and finding internal resistance — practice questions

23 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L2 · understanding

    In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 V1.5 \mathrm{~V} is found to be 60 cm60 \mathrm{~cm}. If this cell is replaced by another cell of emf E, the length-of null point increases by 40 cm40 \mathrm{~cm}. The value of EE is x10V\frac{x}{10} V. The value of xx is ____________.

  2. Question 2 · difficulty L2 · understanding

    In a potentiometer arrangement, a cell of emf 1.20 V gives a balance point at 36 cm length of wire. This cell is now replaced by another cell of emf 1.80 V. The difference in balancing length of potentiometer wire in above conditions will be ___________ cm.

  3. Question 3 · difficulty L2 · understanding

    In a potentiometer arrangement, a cell gives a balancing point at 75 cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emf's of two cells respectively is 3 : 2, the difference in the balancing length of the potentiometer wire in above two cases will be ___________ cm.

  4. Question 4 · difficulty L2 · understanding

    In the given circuit of potentiometer, the potential difference E across AB (10 m length) is larger than E 1 and E 2 as well. For key K 1 (closed), the jockey is adjusted to touch the wire at point J 1 so that there is no deflection in the galvanometer. Now the first battery (E 1 ) is replaced by second battery (E 2 ) for working by making K 1 open and K 2 closed. The galvanometer gives then null deflection at J 2 . The value of E1E2{{{E_1}} \over {{E_2}}} is ab{a \over b}, where a = _________.

  5. Question 5 · difficulty L2 · understanding

    With the help of potentiometer, we can determine the value of emf of a given cell. The sensitivity of the potentiometer is (A) directly proportional to the length of the potentiometer wire (B) directly proportional to the potential gradient of the wire (C) inversely proportional to the potential gradient of the wire (D) inversely proportional to the length of the potentiometer wire Choose the correct option for the above statements :

    • A. A only
    • B. B and D only
    • C. A and C only
    • D. inversely C only
  6. Question 6 · difficulty L3 · understanding

    A null point is found at 200 cm in potentiometer when cell in secondary circuit is shunted by 5Ω\Omega. When a resistance of 15Ω\Omega is used for shunting, null point moves to 300 cm. The internal resistance of the cell is ___________Ω\Omega.

  7. Question 7 · difficulty L3 · understanding

    As shown in the figure, a potentiometer wire of resistance 20Ω20 \,\Omega and length 300 cm300 \mathrm{~cm} is connected with resistance box (R.B.) and a standard cell of emf 4 V4 \mathrm{~V}. For a resistance 'RR' of resistance box introduced into the circuit, the null point for a cell of 20mV20 \,\mathrm{mV} is found to be 60 cm60 \mathrm{~cm}. The value of 'RR' is ___________ Ω.\Omega .

  8. Question 8 · difficulty L3 · understanding

    A potentiometer wire of length 300 cm300 \mathrm{~cm} is connected in series with a resistance 780 Ω\Omega and a standard cell of emf 4V4 \mathrm{V}. A constant current flows through potentiometer wire. The length of the null point for cell of emf 20mV20\, \mathrm{mV} is found to be 60 cm60 \mathrm{~cm}. The resistance of the potentiometer wire is ____________ Ω\Omega.

  9. Question 9 · difficulty L3 · understanding

    The circuit diagram of potentiometer used to measure the internal resistance of a cell (E) is shown in figure. The key 'K' is kept closed so as to send constant current through potentiometer wire. When key 'K 1 ' is kept open the null point is found to be at 120 cm on the potentiometer wire. When the key 'K 1 ' is closed the null point is shifted at 80 cm at the potentiometer wire. The internal resistance of the given cell is _____________ Ω\Omega.

  10. Question 10 · difficulty L3 · understanding

    A cell, shunted by a 8 Ω\Omega resistance, is balanced across a potentiometer wire of length 3 m. The balancing length is 2 m when the cell is shunted by 4 Ω\Omega resistance. The value of internal resistance of the cell will be ____________ Ω\Omega.

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