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NEET-UG Biology

Force on a current-carrying conductor — practice questions

50 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L1 · recall

    The magnetic force on a straight conductor of vector length L carrying current I in field B is

    • A. I(L · B)
    • B. IB/L
    • C. I(L × B)
    • D. IL/B
  2. Question 2 · difficulty L1 · understanding

    A current-carrying wire is parallel to a uniform magnetic field. The force on the wire is

    • A. ILB
    • B. ILB/2
    • C. IB/L
    • D. zero
  3. Question 3 · difficulty L2 · understanding

    A circular coil of radius 2 cm and 125 turns carries a current of 1 A . The coil is placed in a uniform magnetic field of magnitude 0.4 T . The axis of the coil makes an angle of 3030^{\circ} with the direction of the magnetic field. The torque acting on the coil is α×104 N.m\alpha \times 10^{-4} \mathrm{~N} . \mathrm{m}. The value of α\alpha is ____\_\_\_\_ . (π=3.14) (\pi=3.14)

  4. Question 4 · difficulty L2 · understanding

    A 4.0 cm long straight wire carrying a current of 8 A is placed perpendicular to a uniform magnetic field of strength 0.15 T . The magnetic force on the wire is ________mN .

  5. Question 5 · difficulty L2 · understanding

    A straight wire AB\mathrm{AB} of mass 40 g40 \mathrm{~g} and length 50 cm50 \mathrm{~cm} is suspended by a pair of flexible leads in uniform magnetic field of magnitude 0.40 T0.40 \mathrm{~T} as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is ___________ A. (\left(\right. Take g=10 ms2g=10 \mathrm{~ms}^{-2} ).

  6. Question 6 · difficulty L2 · understanding

    Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10 -5 N, then separation between the wires is ____________ cm.

  7. Question 7 · difficulty L2 · understanding

    A uniform magnetic field of 2×103 T2 \times 10^{-3} \mathrm{~T} acts along positive YY-direction. A rectangular loop of sides 20 cm20 \mathrm{~cm} and 10 cm10 \mathrm{~cm} with current of 5 A5 \mathrm{~A} is in YZY-Z plane. The current is in anticlockwise sense with reference to negative XX axis. Magnitude and direction of the torque is:

    • A. 2×104 N2 \times 10^{-4} \mathrm{~N}- m\mathrm{m} along negative ZZ-direction
    • B. 2×104 N2 \times 10^{-4} \mathrm{~N} - m\mathrm{m} along positive XX-direction
    • C. 2×104 N2 \times 10^{-4} \mathrm{~N} - m\mathrm{m} along positive YY-direction
    • D. 2×104 N2 \times 10^{-4} \mathrm{~N} - m\mathrm{m} along positive ZZ-direction
  8. Question 8 · difficulty L2 · understanding

    An electron is moving along the positive x\mathrm{x}-axis. If the uniform magnetic field is applied parallel to the negative z-axis, then A. The electron will experience magnetic force along positive y-axis B. The electron will experience magnetic force along negative y-axis C. The electron will not experience any force in magnetic field D. The electron will continue to move along the positive x\mathrm{x}-axis E. The electron will move along circular path in magnetic field Choose the correct answer from the options given below:

    • A. A and E only
    • B. B and D only
    • C. B and E only
    • D. C and D only
  9. Question 9 · difficulty L2 · understanding

    An electron is allowed to move with constant velocity along the axis of current carrying straight solenoid. A. The electron will experience magnetic force along the axis of the solenoid. B. The electron will not experience magnetic force. C. The electron will continue to move along the axis of the solenoid. D. The electron will be accelerated along the axis of the solenoid. E. The electron will follow parabolic path-inside the solenoid. Choose the correct answer from the options given below:

    • A. B, C and D only
    • B. B and C only
    • C. A and D only
    • D. B and E only
  10. Question 10 · difficulty L2 · understanding

    A current carrying rectangular loop PQRS is made of uniform wire. The length PR=QS=5 cmP R=Q S=5 \mathrm{~cm} and PQ=RS=100 cmP Q=R S=100 \mathrm{~cm}. If ammeter current reading changes from I to 2I2 I, the ratio of magnetic forces per unit length on the wire PQP Q due to wire RSR S in the two cases respectively (fPQI:fPQ2t)\left(f_{P Q}^I: f_{P Q}^{2 t}\right) is:

    • A. 1 : 4
    • B. 1 : 3
    • C. 1 : 2
    • D. 1 : 5

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