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NEET-UG Biology

Characteristics and transverse nature of electromagnetic waves — practice questions

19 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.

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  1. Question 1 · difficulty L1 · recall

    Electromagnetic waves consist of oscillating

    • A. pressure and density only
    • B. electric charge and mass density only
    • C. electric and magnetic fields
    • D. gravitational potential only
  2. Question 2 · difficulty L1 · understanding

    In an electromagnetic wave in vacuum, E and B are

    • A. parallel to each other
    • B. both longitudinal
    • C. randomly oriented with no relation
    • D. perpendicular to each other and to the direction of propagation
  3. Question 3 · difficulty L2 · understanding

    The speed of electromagnetic waves in vacuum is

    • A. c = 1/sqrt(μ0ε0)
    • B. sqrt(μ0ε0)
    • C. μ0/ε0
    • D. 1/(μ0ε0)
  4. Question 4 · difficulty L2 · application

    For a plane electromagnetic wave in vacuum, the field amplitudes satisfy

    • A. E0B0=c
    • B. E0/B0 = c
    • C. E0/B0=1/c
    • D. E0=B0 in identical SI units
  5. Question 5 · difficulty L3 · application

    Electromagnetic waves can propagate through vacuum because

    • A. they are mechanical vibrations of air
    • B. vacuum contains ordinary sound particles
    • C. they do not require a material medium
    • D. they require conduction current everywhere
  6. Question 6 · difficulty L3 · application

    If the electric field of a plane wave points along +y and the magnetic field along +z, the wave propagates along

    • A. -x
    • B. +y
    • C. -z
    • D. +x
  7. Question 7 · difficulty L3 · understanding

    The electric field in a plane electromagnetic wave is given by Ez=60cos(5x+1.5×109t)V/m E_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) \mathrm{V} / \mathrm{m} Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :

    • A. Bz=60cos(5x+1.5×109t)TB z=60 \cos \left(5 x+1.5 \times 10^9 t\right) T
    • B. By=60sin(5x+1.5×109t)TB_y=60 \sin \left(5 x+1.5 \times 10^9 t\right) T
    • C. By=2×107cos(5x+1.5×109t)TB_y=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) T
    • D. Bx=2×107cos(5x+1.5×109t)TB_x=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) T
  8. Question 8 · difficulty L3 · understanding

    If the ratio of relative permeability and relative permittivity of a uniform medium is 1:41: 4. The ratio of the magnitudes of electric field intensity (E)(E) to the magnetic field intensity (H)(H) of an EM wave propagating in that medium is (Given that μ0ε0=120π\sqrt{\frac{\mu_0}{\varepsilon_0}}=120 \pi):

    • A. 30π:130 \pi: 1
    • B. 1:120π1: 120 \pi
    • C. 60π:160 \pi: 1
    • D. 120π:1120 \pi: 1
  9. Question 9 · difficulty L3 · understanding

    The property which is not of an electromagnetic wave travelling in free space is that:

    • A. They are transverse in nature
    • B. The energy density in electric field is equal to energy density in magnetic field
    • C. They travel with a speed equal to 1μ0ε0\frac{1}{\sqrt{\mu_0 \varepsilon_0}}
    • D. They originate from charges moving with uniform speed
  10. Question 10 · difficulty L3 · understanding

    In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0×1010 Hz2.0 \times 10^{10} \mathrm{~Hz} and amplitude 48 Vm148 ~\mathrm{Vm}^{-1}. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1=3 \times 10^{8} \mathrm{~m} \mathrm{~s}^{-1} )

    • A. 1.6×108 T1.6 \times 10^{-8} \mathrm{~T}
    • B. 1.6×107 T1.6 \times 10^{-7} \mathrm{~T}
    • C. 1.6×106 T1.6 \times 10^{-6} \mathrm{~T}
    • D. 1.6×109 T1.6 \times 10^{-9} \mathrm{~T}

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