Total internal reflection and optical fibres — practice questions
10 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.
Total internal reflection can occur only when light travels
- A. from optically denser to optically rarer medium
- B. from rarer to denser medium only
- C. between equal-index media only
- D. normally onto any interface
The critical angle is the incidence angle in the denser medium for which the refracted ray
- A. returns exactly along the incident ray
- B. travels along the interface
- C. has zero speed
- D. is perpendicular to the interface in the rarer medium
For denser medium refractive index n1 and rarer medium n2, the critical angle C satisfies
- A. sin C=n1/n2
- B. cos C=n2/n1
- C. sin C = n2/n1
- D. tan C=n1-n2
Optical fibres guide light primarily by
- A. ordinary mirror reflection from metal coatings only
- B. diffraction at each turn
- C. absorption and re-emission
- D. total internal reflection at the core-cladding boundary
Why is the refractive index of fibre core chosen higher than that of cladding?
- A. To allow total internal reflection within the core
- B. To make light leave the core at every boundary
- C. To remove refraction entirely at the entrance
- D. To make the critical angle exceed 90°
If n1/n2 increases for a denser-to-rarer interface, the critical angle generally
- A. increases toward 90°
- B. decreases
- C. remains fixed
- D. becomes greater than 180°
A glass-air boundary has n_glass=1.5. The critical angle is closest to
- A. 30°
- B. 60°
- C. 42°
- D. 75°
A ray inside glass hits a glass-air interface at an angle below the critical angle. It will
- A. always undergo TIR
- B. stop at the interface
- C. reflect with 100% intensity by definition
- D. partly refract into air rather than undergo total internal reflection
Which practical device most directly exploits repeated total internal reflection?
- A. Optical fibre communication cable
- B. Simple opaque screen
- C. Resistive heater
- D. Galvanometer shunt
A ray in a fibre core is changed so its incidence at the core-cladding interface falls below the critical angle. The most likely result is
- A. stronger confinement by TIR
- B. increased leakage into the cladding
- C. zero refraction at the boundary
- D. automatic increase of core index
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