Young's modulus of a metallic wire — practice questions
10 questions in the bank on this idea. Below are 10 of them, exactly as they appear in a test.
Young's modulus is defined as
- A. strain divided by stress
- B. force divided by length only
- C. longitudinal stress divided by longitudinal strain within the elastic limit
- D. extension divided by area
The SI unit of Young's modulus is
- A. metre
- B. newton only
- C. joule per second
- D. pascal
For a wire of length L, area A and extension ΔL under force F, Young's modulus is
- A. FL/(AΔL)
- B. FΔL/(AL)
- C. AFL/ΔL
- D. F/(LΔL)
If the same force is applied to two wires of the same material and length, the thicker wire extends
- A. more
- B. less
- C. the same amount
- D. an amount independent of area
If wire length doubles with force, area and material unchanged, extension
- A. halves
- B. quadruples
- C. doubles
- D. stays unchanged
A wire has radius r. If radius doubles at fixed F, L and Y, extension becomes
- A. one-half
- B. twice
- C. four times
- D. one-fourth
Why should loads be added gradually in a Young's modulus experiment?
- A. To avoid shocks and help keep deformation within the elastic limit
- B. To change the material's Young's modulus deliberately
- C. To make wire area increase without bound
- D. To eliminate gravity
A load-extension graph is linear through the origin over a range. The wire in that range is obeying
- A. radioactive decay
- B. Hooke's law
- C. Snell's law
- D. Kirchhoff's loop law only
If diameter measurement has a small percentage error, why can it strongly affect calculated Y?
- A. Y depends only on diameter linearly
- B. diameter never enters the formula
- C. Area depends on diameter squared
- D. length is the square of diameter
A wire of length 2 m and area 1×10^-6 m² extends 1 mm under 100 N. Young's modulus is
- A. 2×10^8 Pa
- B. 5×10^10 Pa
- C. 1×10^14 Pa
- D. 2×10^11 Pa
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