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NEET-UG and JEE Main Chemistry · Class 11

Homolytic and heterolytic fission; radicals, carbocations and carbanions — NEET & JEE Questions

Homolytic and heterolytic fission; radicals, carbocations and carbanions is a topic in Some Basic Principles of Organic Chemistry, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Homolytic and heterolytic fission; radicals, carbocations and carbanions, each with the marking scheme of the real paper.

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Homolytic and heterolytic fission; radicals, carbocations and carbanions MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    What is formed when a covalent bond undergoes homolytic fission?

    • A. Two free radicals, each receiving one bonding electron
    • B. A carbocation and a carbanion
    • C. Two cations
    • D. Two anions
  2. Question 2 · difficulty L2 · understanding

    What distinguishes heterolytic fission from homolytic fission?

    • A. In heterolytic fission each atom gets one electron
    • B. In heterolytic fission one atom receives both bonding electrons
    • C. Heterolytic fission never produces charged species
    • D. Heterolytic fission can occur only in non-polar bonds
  3. Question 3 · difficulty L2 · understanding

    Which species is a carbocation?

    • A. CH3+CH_3^+
    • B. CH3−CH_3^-
    • C. CH3⋅CH_3\cdot
    • D. CH4CH_4
  4. Question 4 · difficulty L2 · understanding

    Which statement about a carbanion is correct?

    • A. It is electron-deficient and positively charged
    • B. It contains a negatively charged carbon with a lone pair
    • C. It contains an unpaired electron but no charge
    • D. It is always electrically neutral
  5. Question 5 · difficulty L3 · application

    Homolytic cleavage of the C–Cl bond in CH3ClCH_3Cl would produce which pair of species?

    • A. CH3+CH_3^+ and Cl−Cl^-
    • B. CH3−CH_3^- and Cl+Cl^+
    • C. CH3⋅CH_3\cdot and Cl⋅Cl\cdot
    • D. CH4CH_4 and Cl−Cl^-
  6. Question 6 · difficulty L3 · application

    If the C–Br bond in CH3BrCH_3Br breaks heterolytically with both bonding electrons going to bromine, which products form?

    • A. CH3+CH_3^+ and Br−Br^-
    • B. CH3−CH_3^- and Br+Br^+
    • C. CH3⋅CH_3\cdot and Br⋅Br\cdot
    • D. CH4CH_4 and Br+Br^+
  7. Question 7 · difficulty L3 · application

    Which carbocation is expected to be the most stable among the following simple alkyl carbocations?

    • A. Methyl carbocation
    • B. Primary carbocation
    • C. Secondary carbocation
    • D. Tertiary carbocation
  8. Question 8 · difficulty L3 · application

    Among methyl, primary, secondary and tertiary simple alkyl carbanions, which is generally the most stable?

    • A. Methyl carbanion
    • B. Primary carbanion
    • C. Secondary carbanion
    • D. Tertiary carbanion
  9. Question 9 · difficulty L4 · application

    Which pairing of bond fission and product type is correct?

    • A. Homolytic fission → ions; heterolytic fission → radicals
    • B. Homolytic fission → radicals; heterolytic fission → ions
    • C. Both types always give radicals
    • D. Both types always give ions
  10. Question 10 · difficulty L4 · application

    A carbon–halogen bond undergoes heterolytic cleavage. Which factor most directly determines which atom takes the bonding electron pair?

    • A. The more electronegative atom is generally favored to take the pair
    • B. The less electronegative atom must always take the pair
    • C. The larger atom must always become positive
    • D. The atom with fewer neutrons takes both electrons

Common mistakes in Homolytic and heterolytic fission; radicals, carbocations and carbanions

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Memorises one substitution trend and applies it to both positively and negatively charged carbon intermediates.
  • Identifies the product charges correctly but fails to track where both bonding electrons must go in each cleavage mode.

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