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NEET-UG and JEE Main Physics · Class 11

Parallel and perpendicular axes theorems — NEET & JEE Questions

Parallel and perpendicular axes theorems is a topic in Rotational Motion, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Parallel and perpendicular axes theorems, each with the marking scheme of the real paper.

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Parallel and perpendicular axes theorems MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    The parallel-axis theorem for moment of inertia is

    • A. I=ICM+Md2I=I_{CM}+Md^2
    • B. I=ICM−Md2I=I_{CM}-Md^2
    • C. I=MdI=Md
    • D. I=ICM+MdI=I_{CM}+Md
  2. Question 2 · difficulty L2 · understanding

    The perpendicular-axis theorem is applicable to

    • A. a plane lamina
    • B. any arbitrary three-dimensional body
    • C. only a point mass
    • D. only a sphere
  3. Question 3 · difficulty L2 · understanding

    For a plane lamina in the xy-plane, the perpendicular-axis theorem gives

    • A. Iz=Ix+IyI_z=I_x+I_y
    • B. Ix=Iy+IzI_x=I_y+I_z
    • C. Iz=Ix−IyI_z=I_x-I_y
    • D. IxIy=IzI_xI_y=I_z
  4. Question 4 · difficulty L2 · understanding

    In the parallel-axis theorem, dd represents

    • A. the perpendicular distance between the two parallel axes
    • B. the radius of the body
    • C. the distance from every particle to the axis
    • D. the diameter of gyration
  5. Question 5 · difficulty L3 · application

    A body of mass 2 kg has moment of inertia 0.50 kg m20.50\,\text{kg m}^2 about a centre-of-mass axis. What is its moment of inertia about a parallel axis 0.30 m away?

    • A. 0.18 kg m²
    • B. 0.50 kg m²
    • C. 0.68 kg m²
    • D. 0.80 kg m²
  6. Question 6 · difficulty L3 · application

    A thin circular disc has moment of inertia Iz=12MR2I_z=\frac12MR^2 about its central axis perpendicular to the plane. By symmetry Ix=IyI_x=I_y. What is IxI_x about a diameter?

    • A. 14MR2\frac14MR^2
    • B. 12MR2\frac12MR^2
    • C. MR2MR^2
    • D. 18MR2\frac18MR^2
  7. Question 7 · difficulty L3 · application

    A thin ring has moment of inertia MR2MR^2 about its central axis perpendicular to its plane. What is its moment of inertia about any diameter?

    • A. 12MR2\frac12MR^2
    • B. MR2MR^2
    • C. 2MR22MR^2
    • D. 14MR2\frac14MR^2
  8. Question 8 · difficulty L3 · application

    A rod has centre-of-mass moment of inertia ML2/12ML^2/12 about an axis perpendicular to its length. What is the moment of inertia about a parallel axis through one end?

    • A. ML2/3ML^2/3
    • B. ML2/12ML^2/12
    • C. ML2/4ML^2/4
    • D. 7ML2/127ML^2/12
  9. Question 9 · difficulty L4 · application

    A uniform disc of mass M and radius R has moment of inertia MR2/4MR^2/4 about a diameter. What is its moment of inertia about an axis parallel to this diameter and tangent to the disc?

    • A. 54MR2\frac54MR^2
    • B. 12MR2\frac12MR^2
    • C. 34MR2\frac34MR^2
    • D. 32MR2\frac32MR^2
  10. Question 10 · difficulty L4 · application

    For a thin rectangular lamina, moments about two perpendicular in-plane axes through the centre are Ix=2I_x=2 and Iy=3I_y=3 kg m². What is the moment about the perpendicular central axis?

    • A. 1 kg m²
    • B. 5 kg m²
    • C. 6 kg m²
    • D. 9 kg m²

Common mistakes in Parallel and perpendicular axes theorems

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Assumes moving the axis outward can reduce rotational inertia.
  • Uses the diametral moment $MR^2/4$ as the starting axis instead of the parallel central perpendicular axis.

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