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NEET-UG and JEE Main Physics · Class 11

Equation of state of a perfect gas; work done compressing a gas — NEET & JEE Questions

Equation of state of a perfect gas; work done compressing a gas is a topic in Kinetic Theory of Gases, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Equation of state of a perfect gas; work done compressing a gas, each with the marking scheme of the real paper.

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Equation of state of a perfect gas; work done compressing a gas MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    The equation of state for an ideal gas is

    • A. PV=nRTPV=nRT
    • B. P=nR/TP=nR/T
    • C. PV=RT/nPV=RT/n
    • D. PVT=nRPVT=nR
  2. Question 2 · difficulty L2 · understanding

    For a fixed amount of ideal gas at constant temperature, if the volume is halved, the pressure becomes

    • A. half
    • B. unchanged
    • C. double
    • D. four times
  3. Question 3 · difficulty L2 · understanding

    For a fixed amount of ideal gas at constant pressure, volume is directly proportional to

    • A. absolute temperature
    • B. Celsius temperature only
    • C. inverse absolute temperature
    • D. molar mass only
  4. Question 4 · difficulty L2 · understanding

    When an ideal gas is compressed, the work done by an external agent on the gas is

    • A. necessarily negative under the convention 'work on gas positive'
    • B. positive under the convention 'work on gas positive'
    • C. always zero
    • D. independent of the process path
  5. Question 5 · difficulty L3 · application

    One mole of an ideal gas is at 300 K300\,\text{K} and occupies 24.6 L24.6\,\text{L}. Approximately what is its pressure? Take R=8.31 J mol−1K−1R=8.31\,\text{J mol}^{-1}\text{K}^{-1}.

    • A. 0.10 bar
    • B. 0.50 bar
    • C. 1.01 bar
    • D. 10.1 bar
  6. Question 6 · difficulty L3 · application

    A fixed amount of ideal gas has pressure 2 bar and volume 3 L at constant temperature. If its volume becomes 6 L, what is the new pressure?

    • A. 0.5 bar
    • B. 1 bar
    • C. 2 bar
    • D. 4 bar
  7. Question 7 · difficulty L3 · application

    A gas expands at constant pressure 2.0×105 Pa2.0\times10^5\,\text{Pa} from 0.010 m30.010\,\text{m}^3 to 0.016 m30.016\,\text{m}^3. What work is done by the gas?

    • A. 600 J
    • B. 1200 J
    • C. 2000 J
    • D. 3200 J
  8. Question 8 · difficulty L3 · application

    A gas is compressed at constant pressure 1.5×105 Pa1.5\times10^5\,\text{Pa} from 8.0×10−3 m38.0\times10^{-3}\,\text{m}^3 to 5.0×10−3 m35.0\times10^{-3}\,\text{m}^3. What is the work done on the gas?

    • A. −450-450 J
    • B. 0 J
    • C. 450 J
    • D. 1200 J
  9. Question 9 · difficulty L4 · application

    A fixed amount of ideal gas changes from state (P,V,T)(P,V,T) to (2P,V,2T)(2P,V,2T). Is this change consistent with the ideal-gas equation?

    • A. Yes
    • B. No, pressure should be 4P4P
    • C. No, temperature should remain TT
    • D. No, volume should double
  10. Question 10 · difficulty L4 · application

    A gas is compressed quasistatically at constant pressure from volume VV to V/2V/2. If the pressure is PP, what is the work done on the gas?

    • A. PV/2PV/2
    • B. PVPV
    • C. 2PV2PV
    • D. −PV/2-PV/2

Common mistakes in Equation of state of a perfect gas; work done compressing a gas

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses Celsius differences rather than the ratio of absolute temperatures.
  • Treats work like a state function determined only by the endpoints.

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