NEET-UG and JEE Main Physics · Class 11
Equation of state of a perfect gas; work done compressing a gas — NEET & JEE Questions
Equation of state of a perfect gas; work done compressing a gas is a topic in Kinetic Theory of Gases, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Equation of state of a perfect gas; work done compressing a gas, each with the marking scheme of the real paper.
- questions
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- shown here
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Equation of state of a perfect gas; work done compressing a gas MCQs with solutions
10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.
The equation of state for an ideal gas is
- A.
- B.
- C.
- D.
For a fixed amount of ideal gas at constant temperature, if the volume is halved, the pressure becomes
- A. half
- B. unchanged
- C. double
- D. four times
For a fixed amount of ideal gas at constant pressure, volume is directly proportional to
- A. absolute temperature
- B. Celsius temperature only
- C. inverse absolute temperature
- D. molar mass only
When an ideal gas is compressed, the work done by an external agent on the gas is
- A. necessarily negative under the convention 'work on gas positive'
- B. positive under the convention 'work on gas positive'
- C. always zero
- D. independent of the process path
One mole of an ideal gas is at and occupies . Approximately what is its pressure? Take .
- A. 0.10 bar
- B. 0.50 bar
- C. 1.01 bar
- D. 10.1 bar
A fixed amount of ideal gas has pressure 2 bar and volume 3 L at constant temperature. If its volume becomes 6 L, what is the new pressure?
- A. 0.5 bar
- B. 1 bar
- C. 2 bar
- D. 4 bar
A gas expands at constant pressure from to . What work is done by the gas?
- A. 600 J
- B. 1200 J
- C. 2000 J
- D. 3200 J
A gas is compressed at constant pressure from to . What is the work done on the gas?
- A. J
- B. 0 J
- C. 450 J
- D. 1200 J
A fixed amount of ideal gas changes from state to . Is this change consistent with the ideal-gas equation?
- A. Yes
- B. No, pressure should be
- C. No, temperature should remain
- D. No, volume should double
A gas is compressed quasistatically at constant pressure from volume to . If the pressure is , what is the work done on the gas?
- A.
- B.
- C.
- D.
Common mistakes in Equation of state of a perfect gas; work done compressing a gas
Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.
- Uses Celsius differences rather than the ratio of absolute temperatures.
- Treats work like a state function determined only by the endpoints.
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